Row-valid and column-valid tables of 1... For what can any row-valid table be permuted into column-valid one?
No such configuration exists under the given conditions.
This is possible for all negative integers .
This is impossible for all positive integers .
This is possible for all positive integers .
Hint 1: Model the table entries as a bipartite graph where rows are connected to the numerical values they contain.
Hint 2: Show that since the table is row-valid, this bipartite graph is -regular (every vertex has degree ).
Hint 3: Apply the Birkhoff-von Neumann Theorem or Hall's Marriage Theorem to decompose the regular bipartite graph into disjoint perfect matchings.
Step 1 (Bipartite Graph Formulation): We represent the table as a bipartite graph . The vertices in represent the rows of the table, and the vertices in represent the column positions/values. An edge exists between row and value if value appears in row .
Step 2 (Regularity and Hall's Condition): Since the table is row-valid, each row contains the numbers exactly once. Thus, the degree of every vertex in is exactly . By symmetric properties, each value appears exactly times in the table, meaning the degree of every vertex in is also exactly . Therefore, is an -regular bipartite graph.
Step 3 (Decomposition into Matchings): Every -regular bipartite graph can be decomposed into exactly disjoint perfect matchings (by the Birkhoff-von Neumann theorem or Hall's Marriage Theorem). Each perfect matching corresponds to selecting exactly one element from each row such that all selected elements are distinct. By assigning each perfect matching to a different column position, we can permute the elements within each row to make the columns valid. Thus, it is possible for all .
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