If LCM of two number is 10 and GCD is 5 then the product of two numbers is ________.

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Accepted Answer

{"content":[{"content":[{"marks":[{"type":"bold"}],"text":"Step 1 (State the Theorem):","type":"text"},{"text":" For any two positive integers ","type":"text"},{"type":"math_inline","attrs":{"latex":"a"}},{"text":" and ","type":"text"},{"type":"math_inline","attrs":{"latex":"b"}},{"text":":","type":"text"}],"type":"paragraph"},{"attrs":{"latex":"\text{Product of the two numbers} = a \times b = \text{LCM}(a, b) \times \text{GCD}(a, b)"},"type":"math_block"},{"content":[{"marks":[{"type":"bold"}],"text":"Step 2 (Substitute the Values):","type":"text"},{"text":" We are given:","type":"text"}],"type":"paragraph"},{"content":[{"content":[{"content":[{"attrs":{"latex":"\text{LCM} = 10"},"type":"math_inline"}],"type":"paragraph"}],"type":"list_item"},{"content":[{"content":[{"attrs":{"latex":"\text{GCD} = 5"},"type":"math_inline"}],"type":"paragraph"}],"type":"list_item"}],"type":"bullet_list"},{"content":[{"text":"Substituting these values into the theorem:","type":"text"}],"type":"paragraph"},{"type":"math_block","attrs":{"latex":"\text{Product} = 10 \times 5 = 50"}},{"content":[{"marks":[{"type":"bold"}],"text":"Step 3 (Conclusion):","type":"text"},{"text":" The product of the two numbers is exactly ","type":"text"},{"marks":[{"type":"code"}],"text":"50","type":"text"},{"text":".","type":"text"}],"type":"paragraph"}],"type":"doc"}

Guide / Hint

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