If x^2 - 4x + 4 = 0, then the value of x^2 is ________.

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{"type":"doc","content":[{"content":[{"marks":[{"type":"bold"}],"text":"Step 1 (Factor the Equation):","type":"text"},{"text":" We are given the quadratic equation:","type":"text"}],"type":"paragraph"},{"attrs":{"latex":"x^2 - 4x + 4 = 0"},"type":"math_block"},{"type":"paragraph","content":[{"text":"This is a perfect square trinomial:","type":"text"}]},{"attrs":{"latex":"(x - 2)^2 = 0 \implies x - 2 = 0 \implies x = 2"},"type":"math_block"},{"type":"paragraph","content":[{"text":"Step 2 (Substitute x into target):","type":"text","marks":[{"type":"bold"}]},{"text":" We want to find the value of ","type":"text"},{"attrs":{"latex":"x^2"},"type":"math_inline"},{"text":". Substituting ","type":"text"},{"attrs":{"latex":"x = 2"},"type":"math_inline"},{"text":":","type":"text"}]},{"attrs":{"latex":"x^2 = 2^2 = 4"},"type":"math_block"},{"content":[{"marks":[{"type":"bold"}],"text":"Step 3 (Conclusion):","type":"text"},{"type":"text","text":" The value of "},{"attrs":{"latex":"x^2"},"type":"math_inline"},{"text":" is exactly ","type":"text"},{"marks":[{"type":"code"}],"text":"4","type":"text"},{"text":".","type":"text"}],"type":"paragraph"}]}

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