The distance between the points (-2, 2) and (1, 6) is

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{"type":"doc","content":[{"content":[{"type":"text","marks":[{"type":"bold"}],"text":"Step 1 (Distance Formula):"},{"type":"text","text":" The distance "},{"attrs":{"latex":"d"},"type":"math_inline"},{"text":" between two points ","type":"text"},{"attrs":{"latex":"(x_1, y_1)"},"type":"math_inline"},{"type":"text","text":" and "},{"attrs":{"latex":"(x_2, y_2)"},"type":"math_inline"},{"text":" is given by:","type":"text"}],"type":"paragraph"},{"attrs":{"latex":"d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}"},"type":"math_block"},{"content":[{"marks":[{"type":"bold"}],"text":"Step 2 (Substitute the Coordinates):","type":"text"},{"text":" We are given ","type":"text"},{"type":"math_inline","attrs":{"latex":"(-2, 2)"}},{"text":" and ","type":"text"},{"attrs":{"latex":"(1, 6)"},"type":"math_inline"},{"type":"text","text":". Substituting:"}],"type":"paragraph"},{"attrs":{"latex":"d = \sqrt{(1 - (-2))^2 + (6 - 2)^2}"},"type":"math_block"},{"attrs":{"latex":"d = \sqrt{3^2 + 4^2}"},"type":"math_block"},{"attrs":{"latex":"d = \sqrt{9 + 16} = \sqrt{25} = 5 \text{ units}"},"type":"math_block"},{"content":[{"marks":[{"type":"bold"}],"text":"Step 3 (Conclusion):","type":"text"},{"text":" The distance is 5 units, which is option index ","type":"text"},{"marks":[{"type":"code"}],"text":"1","type":"text"},{"text":" in the list ","type":"text"},{"text":"['25 units', '5 units', '7 units', 'none of these']","type":"text","marks":[{"type":"code"}]},{"text":".","type":"text"}],"type":"paragraph"}]}

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