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Difficulty: 2/102022 NMTC 2022 (QII-70)

In a circle, a pair of chords that subtend congruent (equal) central angles must be:

Options:

  • congruent (equal in length)

  • B.

    perpendicular to each other

  • C.

    parallel to each other

  • D.

    of different lengths

Guide / Hint

Hint 1: Draw radii from the center to the endpoints of both chords to form two triangles.

Hint 2: Apply the Side-Angle-Side (SAS) congruence theorem to these two triangles.

Hint 3: Since the triangles are congruent, their third sides (the chords) must be equal in length. This is at option index 0.

Solution

Step 1 (Construct triangles): Let the circle have center . Let chord 1 be and chord 2 be . Both chords subtend congruent central angles, so:

Step 2 (Apply Side-Angle-Side Congruence): Consider and :

  • (radii of the circle)

  • (radii of the circle)

  • (given congruent central angles)

By the Side-Angle-Side (SAS) congruence criterion:

Step 3 (Corresponding parts of congruent triangles): Since the triangles are congruent, their corresponding side lengths must be equal:

This proves that the two chords are congruent (equal in length).

Step 4 (Conclusion): The chords must be congruent (equal in length), corresponding to option index 0.

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    2022 NMTC 2022 QII-70 - Olympiad Math Olympiad Question | Leminno