What is the sum of all the positive divisors of 600?

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{"content":[{"content":[{"marks":[{"type":"bold"}],"text":"Step 1 (Prime Factorization):","type":"text"},{"type":"text","text":" We find the prime factorization of 600:"}],"type":"paragraph"},{"attrs":{"latex":"600 = 8 \times 75 = 2^3 \times 3^1 \times 5^2"},"type":"math_block"},{"content":[{"text":"Step 2 (Sum of Divisors Formula):","type":"text","marks":[{"type":"bold"}]},{"text":" The sum of all positive divisors ","type":"text"},{"attrs":{"latex":"\sigma(N)"},"type":"math_inline"},{"text":" of a number ","type":"text"},{"attrs":{"latex":"N = p^a q^b r^c"},"type":"math_inline"},{"type":"text","text":" is:"}],"type":"paragraph"},{"type":"math_block","attrs":{"latex":"\sigma(N) = (1 + p + p^2 + \dots + p^a)(1 + q + \dots + q^b)(1 + r + \dots + r^c)"}},{"content":[{"text":"For 600, this is:","type":"text"}],"type":"paragraph"},{"attrs":{"latex":"\sigma(600) = (1 + 2 + 4 + 8)(1 + 3)(1 + 5 + 25)"},"type":"math_block"},{"attrs":{"latex":"\sigma(600) = 15 \times 4 \times 31 = 60 \times 31 = 1860"},"type":"math_block"},{"content":[{"text":"Step 3 (Conclusion):","type":"text","marks":[{"type":"bold"}]},{"text":" The sum of all positive divisors is ","type":"text"},{"attrs":{"latex":"1860"},"type":"math_inline"},{"text":", which corresponds to option index ","type":"text"},{"marks":[{"type":"code"}],"text":"1","type":"text"},{"text":" in ","type":"text"},{"marks":[{"type":"code"}],"text":"['2060', '1860', '2160', '1890']","type":"text"},{"text":".","type":"text"}],"type":"paragraph"}],"type":"doc"}

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