Determine the sum of all possible surface areas of a cube two of whose vertices are (1, 2, 0) and (3

Question

Determine the sum of all possible surface areas of a cube two of whose vertices are (1, 2, 0) and (3, 3, 2).

Accepted Answer

{"type":"doc","content":[{"content":[{"text":"Step 1:","type":"text","marks":[{"type":"bold"}]},{"text":" SA = 6 \times  4 + 1 + 4 ","type":"text"}],"type":"paragraph"},{"content":[{"marks":[{"type":"bold"}],"text":"Step 2:","type":"text"},{"type":"text","text":" = 54 sq.unit2"}],"type":"paragraph"},{"content":[{"marks":[{"type":"bold"}],"text":"Step 3:","type":"text"},{"text":" 3            9","type":"text"}],"type":"paragraph"},{"type":"paragraph","content":[{"marks":[{"type":"bold"}],"text":"Step 4:","type":"text"},{"type":"text","text":" a=          SA = 6   = 27 sq unit"}]},{"type":"paragraph","content":[{"marks":[{"type":"bold"}],"text":"Step 5:","type":"text"},{"text":" 2           2","type":"text"}]},{"content":[{"marks":[{"type":"bold"}],"text":"Step 6:","type":"text"},{"text":" SA = 6a2 = 6 × 3 = 18 sq.unit2","type":"text"}],"type":"paragraph"},{"content":[{"type":"text","marks":[{"type":"bold"}],"text":"Step 7:"},{"text":" => Possible SA = 18 + 27 + 54 = 99","type":"text"}],"type":"paragraph"}]}

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