Consider square ABCD of side length 16. Let E, F be points on CD such that CE = EF = FD. Let the line BF and AE meet in M. The area of MAB is:
Hint 1: Start by analyzing the initial conditions and setting up the basic equations. Eq of line AE: 2y – 3x + 16 = 0.
Hint 2: Look for algebraic properties, symmetry, or geometric theorems to simplify. Eq of line BF: 2y + 3x – 32 = 0.
Hint 3: Proceed with the final algebraic steps to solve the system. => M (8, 4).
Step 1: Eq of line AE: 2y – 3x + 16 = 0
Step 2: Eq of line BF: 2y + 3x – 32 = 0
Step 3: => M (8, 4)
Step 4: Area of AMB
Step 5: 16 16 1 = ( −16 ( 8 ) + 1( 64 − 8 \times 16 ) )
Step 6: 1 1
Step 7: 2 2
Step 8: = ( −16 \times 16 + 64 )
Step 9: = ( 4 – 16 ) = 8 \times 12
Step 10: = 96 sq.units
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