A quadruple (a, b, c, d) of distinct integers is said to be balanced if + = + d. Let S be any set of quadruples (a, b, c, d) where 1 < < < 20 and where the cardinality of S is 4411. Find the least number of balanced quadruples in S.
Hint 1: Start by analyzing the initial conditions and setting up the basic equations. a + = + a<b<d<c.
Hint 2: Look for algebraic properties, symmetry, or geometric theorems to simplify. a + = 37 (20, 17), (18, 19) → 2 → 1 way.
Hint 3: Proceed with the final algebraic steps to solve the system. a + solve for the final value (20, 16), (19, 17) → 2 → 1 way.
Step 1: a + = + a<b<d<c
Step 2: a + = 37 (20, 17), (18, 19) → 2 → 1 way
Step 3: a + = 36 (20, 16), (19, 17) → 2 → 1 way
Step 4: a + = 35 (20, 15), (19, 16), (18, 17) → 3 → 3C
Step 5: a + = 34 (20, 14), (19, 15), (18, 16) → 3 → 3C
Step 6: a + = 33 (20, 13), (19, 14)…(18, 15), (17, 16) → 4 → 4C
Step 7: a + = 32 (20, 12), (19, 13)…(17, 15) → 4
Step 8: a + = 31 (20, 11), (16, 15) → 5
Step 9: a + = 30 (20, 10), (16, 14) → 5
Step 10: a + = 29 → 6 (20, 9)… (15, 14) → 6
Step 11: a + = 28 → 6 (20, 8)\dots.. (15, 13) → 6
Step 12: a + = 27 → 7 (20, 7)\dots. (14, 13) → 7
Step 13: a + = 26 → 7
Step 14: a + = 25 → 8
Step 15: a + = 24 → 8
Step 16: a + = 23 → 9
Step 17: a + = 22 → 9
Step 18: a + = 21 → 10 (20, 1)…. (11, 10)
Step 19: a + = 20 → 9 (19, 1), (18, 2) \dots.. (11, 9)
Step 20: a + = 19 → 9 (18, 1)…. (11, 9)
Step 21: a + = 18 → 8 (17, 1), (10, 8)
Step 22: a+c=5→2 (4, 1) (3, 2)
Step 23: ( )
Step 24: Total balanced quadruple = 4 2 C2 + 3C2 \dots 9C2 + 10C2
Step 25: = 4 10C3 + 10C2
Step 26: 4 \times 10 \times 9 \times 8
Step 27: = + 45 = 525
Step 28: 4 – 4411 = 434
Step 29: For least balanced = 525 – 434 = 91
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