In trapezoid ABCD, the internal bisector of angle A intersects the base BC (or its extension) at the point E. Inscribed in the triangle ABE is circle touching the side AB at M and side BE at the point P. Find the DAE in degrees, if AB : MP = 2.
Hint 1: Start by analyzing the initial conditions and setting up the basic equations. Given, PM .
Hint 2: Look for algebraic properties, symmetry, or geometric theorems to simplify. BAE = AEB = .
Hint 3: Proceed with the final algebraic steps to solve the system. By symmetry M is mid-point of BA.
Step 1: Given, PM
Step 2: ∠BAE = ∠AEB =
Step 3: By symmetry M is mid-point of BA
Step 4: => y => xy
Step 5: => ∠B = 60° => ∠A = 60°
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